Posted by: smitty45
on September 14, 2003 04:32 AM
No. You're not understanding the case. They only have to show that Unix copyrighted (trademarked) code, that was released under "their" given license, is present in Linux.
That means that they can show portions of code that is in AIX, IRIX, or whatever, so long as it's code that was licensed, by them, as "Unix".
So yes, SCO has to show code, and whether it's publicly shown, or only within the trial setting, it does NOT have to be SCO's own code for UnixWare. All that matters is that it's code that is/was licensed under the trademark of "Unix" which they own the trademark on.
The code that came out of the presentation in Europe was code that came *BEFORE* SCO owned the trademark, and was publicly available, therefore not applicable.
Seriously....you gotta understand what the case is about before you comment on it.
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Re:The real reason SCO won't identify the code
Posted by: smitty45 on September 14, 2003 04:32 AMThat means that they can show portions of code that is in AIX, IRIX, or whatever, so long as it's code that was licensed, by them, as "Unix".
So yes, SCO has to show code, and whether it's publicly shown, or only within the trial setting, it does NOT have to be SCO's own code for UnixWare. All that matters is that it's code that is/was licensed under the trademark of "Unix" which they own the trademark on.
The code that came out of the presentation in Europe was code that came *BEFORE* SCO owned the trademark, and was publicly available, therefore not applicable.
Seriously....you gotta understand what the case is about before you comment on it.
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