which works by setting the output record separator to a newline, then prints all members of a list using the implicit $_ variable, and separates them with the output record separator.
Just to show that you can do a lot with perl's carefully chosen 'default' variables mentioned in the article.
If you replace the middle semicolon with a &&, it becomes '($\ = "\n") && print for @users;' quite close to unreadable for a perl newbie, but nevertheless a valid perl one-liner.
BTW: the loop in de code above is not needed, ie. it is allowed to remove the 'for'. </TT>
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Re:The Perl way of iterating over an array
Posted by: Administrator on July 08, 2004 03:34 PM@users = (eric, billy, eddie, yngwie);
$\ = "\n" ; print for @users;
which works by setting the output record separator to a newline, then prints all members of a list using the implicit $_ variable, and separates them with the output record separator.
Just to show that you can do a lot with perl's carefully chosen 'default' variables mentioned in the article.
If you replace the middle semicolon with a &&, it becomes '($\ = "\n") && print for @users;' quite close to unreadable for a perl newbie, but nevertheless a valid perl one-liner.
BTW: the loop in de code above is not needed, ie. it is allowed to remove the 'for'.
</TT>
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