I'm wondering is there a script/program/method to determine which memory allocator (slab, slub, or slob) the kernel is using?

egrep "SLAB|SLOB|SLUB" /usr/src/linux/.config I'm using SLUB, as the output shows: CONFIG_SLUB_DEBUG=y <---------------- # CONFIG_SLAB is not set CONFIG_SLUB=y <---------------- # CONFIG_SLOB is not set CONFIG_SLABINFO=n # CONFIG_SLUB_DEBUG_ON is not set

Thanks for the reply. I guess I should be more specific. Looking at the .config in the kernel's source location is an "ok" method, but it is fallible. You have to make the assumption that you have the same kernel loaded from that source location, it doesn't necessarily tell you how the kernel you have currently loaded is configured. Perhaps I'm a bit paranoid, but I'm just looking to see if there is an easy way to query the kernel itself.

Try cat /proc/meminfo | egrep -i "SLAB|SLOB|SLUB" or egrep -i "SLAB|SLOB|SLUB" /proc/meminfo

unfortunately, slub and slob where made as dropin replacements for slab.. so the "Slab: xxxxx kB" reported doesn't indicate the type of management used. At least this is my understanding. Please correct me if I'm wrong.

My kernel was compiled with slab. So I can't test for anything else. Did you actually run the commands suggested by shamer and me? Another thing to try cat /proc/kallsyms | egrep -i "slab|slub|slob" If you can't trust the symbols table, then I don''t think there is any way to do it. If every symbol refers to slub or slob as slab, then you will have to compile a kernel with your settings in .config to know for sure.

yes, I did look into those commands. The last one I think will work for my purposes. The absence of slub and slob in the /proc/kallsyms, I would think, definitely indicates that slab is being used. Thank you both for your help.