Triple boot - looking to reinstall CentOS 7 without affecting order !
good evening everyone!
I have the following set-up:
an i7 with 2 HDDs:
First HDD) a 3 TB HDD dedicated to a licensed Windows 10 pro 64 bits
Second HDD) a 2 TB HDD shared between 2 linux distros: a CentOS 7 KDE and a Linux Mint 18 Cinnamon (both 64 bits)
I bought this PC as bare-bones (without and os).
First, i proceeded to install the Windows 10 64, on the 3TB HDD (on the first HDD). So windows has an entire HDD all to itself.
Then, on the second HDD, the 2 TB one, i proceeded to install, in the following order:
1) CentOS 7 KDE all inclusive (i used a USB stick to boot and install)
2) Linux Mint 18 Cinnamon with its GRUB2.
So, the Linux Mint 18's GRUB2 controls all booting proccesses and boot order.
On the Linux Mint 18, i also have grub-customizer.
The attached screenshots both show the same thing:
Screenshot 1 --- is the shell with the command df -h
Screenshot 2 -- same thing, except i used the disks utility of Mint 18 Cinnamon
In either screenshot, you will see the following:
- sda: is the 3 TB windows hdd
- sdb: is tne 2 TB hdd which is shared between the linux partitions.
sdb 1, sdb2 and sdb 3 --- all these belong to the CentOS 7 installation
sdb 4, sdb 5 and sdb 6 --- all these belong to the Mint 18 Cinnamon installation (this is the one which also controls the GRUB2)
PROBLEM: seeing as i have an AMD Radeon RX470 4 GBDDR5 graphics board, i tried to install the official drivers in CentOS 7.
This operation went great in Linux Mint 18...but not good at all in CentOS 7!
Now i want to re-install the CentOS 7, but i do not want to mess up the grub2 bootloader (and centos 7 also has grub2!)
if i do a regular re-install it will mess up the GRUb2 by re-writing it!
How precisely do i reinstall CentOS 7, without affecting/re-writing the GRUB2, and without affecting the other OSes boot order?